(x-2)(2x^2+5x-1)=0

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Solution for (x-2)(2x^2+5x-1)=0 equation: 


Simplifying
(x + -2)(2x2 + 5x + -1) = 0

Reorder the terms:
(-2 + x)(2x2 + 5x + -1) = 0

Reorder the terms:
(-2 + x)(-1 + 5x + 2x2) = 0

Multiply (-2 + x) * (-1 + 5x + 2x2)
(-2(-1 + 5x + 2x2) + x(-1 + 5x + 2x2)) = 0
((-1 * -2 + 5x * -2 + 2x2 * -2) + x(-1 + 5x + 2x2)) = 0
((2 + -10x + -4x2) + x(-1 + 5x + 2x2)) = 0
(2 + -10x + -4x2 + (-1 * x + 5x * x + 2x2 * x)) = 0
(2 + -10x + -4x2 + (-1x + 5x2 + 2x3)) = 0

Reorder the terms:
(2 + -10x + -1x + -4x2 + 5x2 + 2x3) = 0

Combine like terms: -10x + -1x = -11x
(2 + -11x + -4x2 + 5x2 + 2x3) = 0

Combine like terms: -4x2 + 5x2 = 1x2
(2 + -11x + 1x2 + 2x3) = 0

Solving
2 + -11x + 1x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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